-
10-20-2004, 07:16 PM #1
FCK!!!! Brain lock on physics question
Workin on some physics hw for the past couple hours and my brain is ready to take a sh.it.....
A nonconductor has an internal electric field that varies radially
E = 5.2 * (V/m^4) * r^3 * (r_vector)
a) Find the E force on an electron at r = .25m
b) Find the change in C from r = 0 to r = .24
c) The electron is released from rest at r = .25m, Find the speed of the electron at r = 0
-
10-20-2004, 07:17 PM #2
Oh yea, let me say thanks in advance..... Im not even lookin for free-bies here, even a couple hints would probably help
-
10-20-2004, 07:54 PM #3
magnetic fields? am i to assume this is a spehere? is that all there is to the detail of the question?
Last edited by Psychotron; 10-20-2004 at 08:03 PM.
-
10-20-2004, 08:10 PM #4
Yup thats why I am stumped, doesnt show a picture at all either
-
10-20-2004, 08:11 PM #5
whats V? I'm assuming m is distance in meters?
And where the F is C in there? lol
-
10-20-2004, 08:26 PM #6
yea, um bump
-
10-20-2004, 08:30 PM #7
V=voltage
-
10-20-2004, 08:38 PM #8
Are you supposed to find it in terms of V cuz i think youve got too many unknowns in one equation... you dont know E and you dont know V
-
10-20-2004, 09:12 PM #9
Originally Posted by AandF6969
I think this is supposed to represent something like an extension cord, or power cord, etc... where m is the length of the extension cord, r is the radius, V is the voltage going through cord, etc. That is all I can think of. Im not sure how to manipulate this formula though to find out E for the first part. I emailed the teacher, hopefully he gets back to me letting me know he forgot to add another part to the question.
-
10-20-2004, 09:14 PM #10
E=mc^2
-
10-20-2004, 09:17 PM #11
Associate Member
- Join Date
- Mar 2004
- Location
- NJ
- Posts
- 447
Buy the sol'ns manual you cheap bastard
-
10-20-2004, 09:20 PM #12
Originally Posted by Powrlftr
-
10-20-2004, 09:22 PM #13
If i knew there was going to be this much physics involved in getting a BA in engineering I woulda went into MIS or something, lol.
-
10-20-2004, 09:38 PM #14
Associate Member
- Join Date
- Mar 2004
- Location
- NJ
- Posts
- 447
Originally Posted by OSTIE
-
10-20-2004, 10:06 PM #15
Now that i think about it m is usually mass... not meters or length
-
10-21-2004, 12:23 AM #16
Originally Posted by AandF6969
-
10-21-2004, 12:52 AM #17
Originally Posted by 1badcamaro
-
10-21-2004, 03:09 AM #18
Ask Todd over at ANABOLICMONSTERZ.com He can answer anything.
-
10-21-2004, 12:55 PM #19
Originally Posted by OSTIE
It ended up being easy as FCK and I didnt get it till i tried to put the r in the equation.... since r is in meters, the bottom of the equation is m^3... cancel that with the m^4 on top and you are left with E in terms of V/m... plug that value into the equation F(e_field) = qE and theres the answer to part A. The rest is all easy after that.
-
10-21-2004, 03:37 PM #20
told you...
all about the mc^2
-
10-21-2004, 04:47 PM #21
good god..what ever happened to addition and subtraction???
Thread Information
Users Browsing this Thread
There are currently 1 users browsing this thread. (0 members and 1 guests)
Next cycle... Just...
Yesterday, 08:17 PM in ANABOLIC STEROIDS - QUESTIONS & ANSWERS