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# Thread: Math People! (Formula Problem)

1. ## Math People! (Formula Problem)

I just posted the same question the education thread...but this area gets more traffic.

E (greek letter "sigma") 500*e^(ln(1/2)n/1.5) from n=0 to n=6.
So 6 = 1300

So I try it...

500*e^(ln(1/2)n/1.5)
500*e^(ln(0.5)6/1.5)
500*e^(-.6931*6/1.5)
500*e^(-2.7724)
500*0.0625
31.26

WTF!!

Man I didn't think it was that long ago that I had to use a natural logarithm.

2. can you be clearer on where exactly you are finding a problem completing this sum? im not even sure what the problem is asking for. it appears to be just a simple sum of an equation from n=o to n=6. meaning you would have to plug in each integer n value between 0 and 6 (1,2,3,4,5,6). then add the results of each substitution together.

does the problem say sigma = 500*e^(ln(1/2)n/1.5) from n=0 to n=6

or is there a sigma in front of 500*e^(ln(1/2)n/1.5) from n=0 to n=6.

i can help ya bro, lets just clear this up some.

3. Originally Posted by flexgolf
can you be clearer on where exactly you are finding a problem completing this sum? im not even sure what the problem is asking for. it appears to be just a simple sum of an equation from n=o to n=6. meaning you would have to plug in each integer n value between 0 and 6 (1,2,3,4,5,6). then add the results of each substitution together.

does the problem say sigma = 500*e^(ln(1/2)n/1.5) from n=0 to n=6

or is there a sigma in front of 500*e^(ln(1/2)n/1.5) from n=0 to n=6.

i can help ya bro, lets just clear this up some.
Fuck I knew it! I should have summed them up. The formula did say sigma...and I over looked it. I summed 0-6 and it worked. Thanks bro.

4. Man I stopped taking math once numbers turned into letters....what kind of bullshit is that? Does our alphabet have numbers in it too?

5. Originally Posted by Money Boss Hustla
Fuck I knew it! I should have summed them up. The formula did say sigma...and I over looked it. I summed 0-6 and it worked. Thanks bro.
yeah the classic sigma sign is for the sum over all integers given by n= whatever (on the bottom of sigma) to the n value on on top of the sigma. cool that it worked though. why did u have to solve that anyways?

6. Check out the link. I want to check my blood levels. I will still have close to 600mg of test enanthate ester in my body when I will start on clomid. Basing it on 500mg and 2 week absorption. Makes me think.

7. yeah it makes me think too. im gonna make a spread sheet based on week by week blood levels for my upcoming cycle.