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  1. #1
    jon rock's Avatar
    jon rock is offline Associate Member
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    A pointless thread

    So you just had to look. I told you it was pointless.

    ok hows about a michael jackson joke

    What time does micheal jackson go to bed?
    when the big hand touches the little hand.

  2. #2
    BOUNCER is offline Retired Vet
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    Your about 50 yrs too late. This has been flogged to death.

  3. #3
    samoth's Avatar
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    Since you are all so bored and making pointless threads and what not, someone should PM me to help me with a relativity problem I'm having trouble figuring out.

    Not that I'm going to keep my hopes up or anything, as when I usually mention the word 'physics', whatever thread I'm on dies.

    So how about them Packers? Griffey get to 500 yet?

  4. #4
    monstercojones's Avatar
    monstercojones is offline The Anabolic Assassin
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    whats the physics problem?

  5. #5
    ChiTownTommy's Avatar
    ChiTownTommy is offline Senior Member
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    packer suck,
    you know why they saw michle jackson at k-mart?
    he heard about the sale, litttle boys underwear half off

  6. #6
    samoth's Avatar
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    Quote Originally Posted by monstercojones
    whats the physics problem?
    Special Relativity

    Relativistic speed of light derived from Newtons second law.

    In classical physics, force is given by
    F=dp/dt
    where p=mv
    so
    F=d/dt (mv)
    =m dv/dt
    =ma

    So using F=m dv/dt
    rearranging
    (F/m) dt=dv
    dv=a dt
    integrating
    int dv=int a dt
    v=a int dt
    v=at

    Where a=F/m is the slope of the line (linear) on a t vs v graph. However, this is wrong, as the line should asymptotically approach a limit of c.

    The problem is that p=mv is wrong in relativistic terms. Relativistically, p=(gamma)mv

    So F=dp/dt
    =d/dt ((gamma)mv)

    BUUUUUT (gamma) depends on v........ so taking the derivative will act on (gamma) which DEPENDS on v.

    I am trying to come up with a (rather complex) integral using substitutions and exponentials to show the actual speed of light barrier which can be reduced to non-relativistic terms when v approaches zero and gamma approaches 1 giving F=(1)ma=ma

    This problem also deals with imaginary numbers, as the example given was the speed of 2c.

    Classically, this gives (gamma)=(1-(v^2/c^2))^(1/2)=(1-4)^(1/2)=1/3i where i=(-1)^(1/2)

    My problem is that I really don't know where to even start.
    I'm thinking I need to use the non-classical definition of momentum p, but where and how?

    [hey, you asked ]

  7. #7
    samoth's Avatar
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    After typing all of that out, I dang well better get some replies. I really don't care what the replies are about, but I better see some here real quick-like.

  8. #8
    bornbad71's Avatar
    bornbad71 is offline Anabolic Member
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    [shaking in my shoes]......... was up with all the chicken scratch????????????

  9. #9
    bornbad71's Avatar
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    Quote Originally Posted by bornbad71
    [shaking in my shoes]......... was up with all the chicken scratch????????????
    This was a pointless post in a pointless thread.

  10. #10
    samoth's Avatar
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    Quote Originally Posted by bornbad71
    This was a pointless post in a pointless thread.
    You're daaaaaaaaammnn right it was.

    Now how about a solution to the problem, huh? I'll be up all night, so if it takes you a while, I'll still be here.

  11. #11
    Cycleon is offline AR-Hall of Famer / Retired
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    well at least we both agree that neither of us would know where to start on that

  12. #12
    spywizard's Avatar
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    silly rabbits...........

    just keeping the insanity going..........
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