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  1. #1
    anadrol50 is offline New Member
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    calculate the dosage of steroids

    do anyone know how to do it ? by body weight, height and bf, converted to mg. cant find anyting on the internett.

  2. #2
    JohnnyVegas's Avatar
    JohnnyVegas is offline Knowledgeable Member- Recognized Member Winner - $100
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    Not sure what you are asking. Are you simply asking how much you should use? If so, there are some simple starter cycles that are easy to find on this site.

    If you have more complicated questions, post up your age, height, weight, body fat, years lifting and goals so people can help out.

  3. #3
    Capebuffalo's Avatar
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    The only calculation you need to figure out at 20 yrs old is your macros for your food and your tdee. Use these calculations to grow and get a good base.

  4. #4
    MuscleInk's Avatar
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    Quote Originally Posted by Capebuffalo View Post
    The only calculation you need to figure out at 20 yrs old is your macros for your food and your tdee. Use these calculations to grow and get a good base.
    Good catch!

    How's the nut sack BTW???

  5. #5
    Capebuffalo's Avatar
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    Quote Originally Posted by MuscleInk View Post
    Good catch!

    How's the nut sack BTW???
    F Ing left one hurts. Thanks for asking...

  6. #6
    MuscleInk's Avatar
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    Quote Originally Posted by Capebuffalo

    F Ing left one hurts. Thanks for asking...
    Gawd bro, I hope that gets better soon. You better be giving the boys their rest!

  7. #7
    anadrol50 is offline New Member
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    i did't ask u to sett up a cycle for me or a diett , I just want to know how to calculate the facking dosage , is there a formula for this?

  8. #8
    Capebuffalo's Avatar
    Capebuffalo is offline - MONITOR -
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    Here Ya go champ

    0 = [log2(x)] [log2(x) – 2]
    log2(x) = 0 or log2(x) – 2 = 0
    20 = x or log2(x) = 2
    1 = x or 22 = x
    1 = x or 4 = x

  9. #9
    freddy1418 is offline Associate Member
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    Quote Originally Posted by anadrol50
    i did't ask u to sett up a cycle for me or a diett , I just want to know how to calculate the facking dosage , is there a formula for this?
    If you don't have the answer to this then you need to read up and do your homework.. were here to help not hold hands... read the stickies there's a lot of good info there. You obviously need to do your homework... I heard there's no such thing as a dumb question but D*M lol Though we've all started were you are...

  10. #10
    freddy1418 is offline Associate Member
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    Quote Originally Posted by Capebuffalo
    Here Ya go champ

    0 = [log2(x)] [log2(x) - 2]
    log2(x) = 0 or log2(x) - 2 = 0
    20 = x or log2(x) = 2
    1 = x or 22 = x
    1 = x or 4 = x
    Lol and Cape is right... at 20 the only math you need is into your diet as stated before...

  11. #11
    Scabtree's Avatar
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    Quote Originally Posted by Capebuffalo View Post
    Here Ya go champ

    0 = [log2(x)] [log2(x) – 2]
    log2(x) = 0 or log2(x) – 2 = 0
    20 = x or log2(x) = 2
    1 = x or 22 = x
    1 = x or 4 = x

    Ha! Cape, that's a good one!

    You should keep that formula for the myriad of under-agers asking about AAS

  12. #12
    anadrol50 is offline New Member
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    ty Capebuffalo

  13. #13
    juice work is offline Banned
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    Quote Originally Posted by anadrol50 View Post
    do anyone know how to do it ? by body weight, height and bf, converted to mg. cant find anyting on the internett.
    are you asking if there is some formula for an exact mg factored in with weight, height, body fat, and age?

    or are you asking if the side of the bottle tells you the mg dosage?

    w*h*bf= fackin read the forums dawg

  14. #14
    auslifta's Avatar
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    Quote Originally Posted by anadrol50 View Post
    do anyone know how to do it ? by body weight, height and bf, converted to mg. cant find anyting on the internett.
    There is no such formula. Generally those things you stated-body weight, height, bf are factors when deciding dosage so is age, training experience, previous cycles and over all health.

  15. #15
    Honkey_Kong's Avatar
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    Quote Originally Posted by Capebuffalo View Post
    Here Ya go champ

    0 = [log2(x)] [log2(x) – 2]
    log2(x) = 0 or log2(x) – 2 = 0
    20 = x or log2(x) = 2
    1 = x or 22 = x
    1 = x or 4 = x
    Hhahahahaha

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