Math Help people

[seriouslifter]

I need a few problems done, I dont remember how to do this, it is so old. The steps how to do them would be great. Thanks it looks so easy.


1. A line has the equation y=5x-2, which of the following points is on this line?


2. Solve the equation 6x-3y = 12 for y:


3. If 5(x-3)+6 = 7x+9 then x=


4.If 3x-2 = -7x+8 then x=


5. 4AB^3C

Let A=2, B=-1, C=-3


6. (3A-2B)(4BC)
Let A=2, B-1, C=-3


7. (3z^4)^3 (-2z^2)=


8. Find the value of the expression

-2w^2 + 12w if w=-2 and x=4
-----
3x

The 12w and 3x is a fraction or divided by you know, the dash is between 12w and 3x.

[l2elapse]

1, a point would be x=1 and y = 3,
2 y = 2x - 4
3 x = -10
4 x=1
5 = -8^9

[l2elapse]

this is basic algrebra, what class are you in?

[l2elapse]

6 is 96

[chest6]

7. (3z^4)^3 (-2z^2)=


8. Find the value of the expression

-2w^2 + 12w if w=-2 and x=4
-----
3x

The 12w and 3x is a fraction or divided by you know, the dash is between 12w and 3x.

This is kinna hard to type..but ill try

7. (3^3 z^12) (-2z^2)

(9z^12) (-2z^2)=-18z^14



8. -2(-2)^2 +12(-2)
_______
3(4)

....

8+(-24)
____
12

8 + (-2)=6


Its been awhile...but I think I got it. N ya...it is basic algebra...what class is this?


Anyone double check me? I haven't done algebra in like 4 years

[chest6]

^^^^^ It wont show the proper part of the problem as being divided...but you get the idea...

[seriouslifter]

its a placement test so im taking sample test, i dont remember any of this

[l2elapse]

its a placement test so im taking sample test, i dont remember any of this

its all good, math is a subject its very easy to lose but you can get it back quick

[seriouslifter]

1, a point would be x=1 and y = 3,
2 y = 2x - 4
3 x = -10
4 x=1
5 = -8^9

how did you do those? those answers are right i guess since i see its one of the choices since multiple choice.

[TheDfromGC]

how did you do those? those answers are right i guess since i see its one of the choices since multiple choice.

y=mx+B b=y intercept (where the line crosses on y axis) therefore, when its -2, one point will be (0,-2) M=slope rise/run

[l2elapse]

#1, just pick a point for X and then plug it in and solve for Y
#2 push everything to one side to have Y by itself
#3 first distribute the 5 for the ( ) then solve for X
#4 solve for X
#5 simple plug and chug
#6 plug and chug the first ( ) and second ( ) then once that is done, multiple both ( ) ( ) together

[seriouslifter]

#1, just pick a point for X and then plug it in and solve for Y
#2 push everything to one side to have Y by itself
#3 first distribute the 5 for the ( ) then solve for X
#4 solve for X
#5 simple plug and chug
#6 plug and chug the first ( ) and second ( ) then once that is done, multiple both ( ) ( ) together

for #2, which side do i push it to?

[Prada]

for #2, which side do i push it to?

Like this
6x-3y = 12 this is your given formula
Step one:Isolate your Y,
-3y=-6x+12
Step two: We want y not 3y, hence divide everything by 3 to get rid of the 3.
-y=-2x+4
Step 2: Having -y is not the standard so, switch signs on everythig.
y=2x-4

Voila you answer