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  1. 06-14-2006, 10:02 PM #1
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    Exclamation A New Math Dilemma!!!

    If you have ONLY $20.00 and you must buy with it 20 animals as a mix of the following three animals:
    sheep $4.00
    chicken $0.50
    bird $.25
    you have to buy at least one of each kind and the number of the animals you have to buy has to be 20 and worth an even $20.00
    so many of each kind will you have?
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  2. 06-14-2006, 10:05 PM #2
    Thug Nasty
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    What the hell kind of math class are you in?
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  3. 06-14-2006, 10:07 PM #3
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    Quote Originally Posted by Thug Nasty
    What the hell kind of math class are you in?
    Calculus
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  4. 06-14-2006, 10:10 PM #4
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    Quote Originally Posted by smokethedays
    Calculus

    ahh, gotta love calc
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  5. 06-14-2006, 10:06 PM #5
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    Quote Originally Posted by smokethedays
    If you have ONLY $20.00 and you must buy with it 20 animals as a mix of the following three animals:
    sheep $4.00
    chicken $0.50
    bird $.25
    you have to buy at least one of each kind and the number of the animals you have to buy has to be 20 and worth an even $20.00
    so many of each kind will you have?

    oh no, not another one of these...

    im too tired to think right now
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  6. 06-14-2006, 10:07 PM #6
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    Quote Originally Posted by Tren Bull
    oh no, not another one of these...

    im too tired to think right now
    common man
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  7. 06-14-2006, 10:07 PM #7
    caddilac
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    3 sheep
    15 chickens
    2 birds
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  8. 06-14-2006, 10:08 PM #8
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    Quote Originally Posted by caddilac
    3 sheep
    15 chickens
    2 birds
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  9. 06-14-2006, 10:10 PM #9
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    Quote Originally Posted by caddilac
    3 sheep
    15 chickens
    2 birds
    man that was goood, not many people were able to do it.
    did u guess it or did it mathematically?
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  10. 06-15-2006, 12:26 AM #10
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    Quote Originally Posted by caddilac
    3 sheep
    15 chickens
    2 birds
    caddilac is right. you don't even need a formula to figure this out. my little bro could probably do it!

    3 sheep = $12
    15 chickens = $7.50
    2 birds = $.50
    TOTAL
    20 animals = $20
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  11. 06-15-2006, 12:34 AM #11
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    Quote Originally Posted by Superhuman
    caddilac is right. you don't even need a formula to figure this out. my little bro could probably do it!

    3 sheep = $12
    15 chickens = $7.50
    2 birds = $.50
    TOTAL
    20 animals = $20
    Ya, if he had Excel... I doubt a calc professor would except that has a correct solution, because in higher math classes like calc, its not about the answer, its about how you arrived at the answer
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  12. 06-15-2006, 12:42 AM #12
    stunner5000pt
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    this isnt a calc question... its more of an elementary linear algebra question
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  13. 06-15-2006, 12:47 AM #13
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    Quote Originally Posted by stunner5000pt
    this isnt a calc question... its more of an elementary linear algebra question
    Ya, im tryin to find some of my old books, but like I said... I thought it was more of a pre-calc class (linear algebra to most).... some schools are different though, so it may be incorporated in a first year calc course as the first chapter or two
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  14. 06-14-2006, 10:09 PM #14
    caddilac
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    only 5 minutes! cmon smoke give us a challenge
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  15. 06-14-2006, 10:11 PM #15
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    what are you in, remedial math?
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  16. 06-14-2006, 10:12 PM #16
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    Quote Originally Posted by Superhuman
    what are you in, remedial math?

    you mean me?
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  17. 06-14-2006, 10:14 PM #17
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    Quote Originally Posted by Superhuman
    what are you in, remedial math?
    KG2
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  18. 06-14-2006, 10:15 PM #18
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    Quote Originally Posted by smokethedays
    KG2

    uhhh, what?
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  19. 06-14-2006, 10:25 PM #19
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    Quote Originally Posted by Tren Bull
    uhhh, what?
    KinderGarten 2
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  20. 06-14-2006, 10:50 PM #20
    stunner5000pt
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    let x = number of sheep
    y = number of chickens
    z = number of birds and
    solve the system of equations

    4x + 0.5y + 0.25 z = 20
    x + y + z = 20

    you will get your answers in parametric form, but we must choose a parameter such that all x ,y ,z values are integers

    i will solve it later
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  21. 06-15-2006, 08:10 PM #21
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    thanks bro
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  22. 06-14-2006, 10:12 PM #22
    caddilac
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    actually i used excel. is that cheating?
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  23. 06-14-2006, 10:13 PM #23
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    Quote Originally Posted by caddilac
    actually i used excel. is that cheating?
    damn cheater

    j/k
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  24. 06-14-2006, 10:18 PM #24
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    BD test enan question

    I just picked up some BD test E. the hologram on the side that has a BD and the dragon is green? All the pics i looked at there all red. Anyone ever see this?
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  25. 06-14-2006, 10:19 PM #25
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    can someone tell me how to post a new thread please?
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  26. 06-14-2006, 10:25 PM #26
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    go to the top of this page and look for the tab that says: Anabolic Steroids - Steroid.com / Anabolic Review Forums on the top left, click it and it'll show you all the categories of the forum. choose the one you want and scroll down a bit and u'll see a tab called new thread. click it then type in the topic of ur thread and then the body and click post.
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  27. 06-15-2006, 12:15 AM #27
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    So off the top of my head.... Solve for 'y' first...

    You get y = (56.25/3.5)t

    Plug this back in for 'y' in the first equation and solve for 'x'.... 'x' will than equal "SOMENUMBER"t

    U place both these values back in the first equation and solve for 't'... once you have the value for 't' you will easily be able to figure out the rest....
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  28. 06-15-2006, 12:17 PM #28
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    Well it would be the answer, since he asked "so (how) many of each kind will you have?"
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  29. 06-15-2006, 08:50 PM #29
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    I would buy a cow for $20 he has more protein
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  30. 06-15-2006, 11:44 PM #30
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    Quote Originally Posted by gsxxr
    I would buy a cow for $20 he has more protein

    mmm, steak. i could go for some of that right about now
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  31. 06-15-2006, 11:47 PM #31
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    Quote Originally Posted by gsxxr
    I would buy a cow for $20 he has more protein


    Mooo!
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