Anyone here good at finite?

[JDawg1536]

not much time to work it out to verify, but the only info you need is there are 3 possibilities (x, y, z) and there are 50 customers. so really you have 50, 50, 50. so i BELIEVE its 50! + 50! + 50! which = 9.12422796 × 10^64. check it out and see. Ill work it out and double check it tomorrow morning around 8am and post a definate answer.

max

I havent taken math in a few years, but i remember doing this stuff. Im pretty sure that number is off. cuz think about it logically. if there were 2 choices how many possibilities would there be? 50 right? so to add one more possibility wouldnt increase the number that much. ill remember how to do it in a few minutes.........

[JDawg1536]

ok i believe you need to use that formula nCr. The odds of all 50 choosing the extra large are just the same as the 50 people picking any other combination. The answer I got was 125,000, dont ask me to explain it tho

http://mathforum.org/pcmi/hstp/sum20...ing/brian.html