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04-26-2011, 03:58 PM #1"Rock" of Love ;)
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- Apr 2002
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Anyone Know Calculus? I Need Help
I need help finding the derivative of (2+x-x^2)/(x+1)^2
I'm using the quotient rule and ****ing it up... Anyone know how to do it?
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04-26-2011, 05:01 PM #2
Hopefully this will help.
http://www.karlscalculus.org/divrules.html
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04-26-2011, 06:31 PM #3
Check the following out.. I tried to break things down as much as I could, as I understand that calculus tends to be a complete culture shock for some of us.
We have this:
(2+x-x^2)/(x+1)^2
--First, reduce the expression by canceling out the common factor terms (x+1) from both numerator and denominator.
ex: -((x+1)(x-2)) / (x+1)(x+1)
--Then, after reducing the above equation, you find the derivative of the expression:
d/dx = -(x-2)/(x+1)
--*As you correctly stated, using the quotient rule, that yields:
d/dx = -(x+1)(x-2)/(x+1)^2
--Simplyfing it a bit further, you get:
d/dx = -(x-2)/(x+1) = 1/((x+1)(x-2)/((x+1)^2)
--Multiplying by the reciprocal:
(1/-(x+1)(x-2))(1/((x+1)^2)
--Finally, you combine common factors (x+1) by exponential sums:
[-1/(x+1)^3(x-2)]
Let me know if you have questions about this.
MaxLast edited by "Maximus"; 04-26-2011 at 06:34 PM.
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04-26-2011, 08:31 PM #4"Rock" of Love ;)
- Join Date
- Apr 2002
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- 4,130
Thanks for you help, man. I'm gonna look things over and see if I can get it now. I'll most likely be back... this shit is whack.
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04-26-2011, 08:54 PM #5
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04-26-2011, 08:55 PM #6
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04-27-2011, 06:09 AM #7
it's been 30 years... sorry!
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04-27-2011, 07:37 AM #8
If it wasn't for the "bell" curve used back when I was in university....would have NEVER passed!
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04-27-2011, 09:16 AM #9
gotta love those curves!
I mean bell curves.... you knew that's what I meant, right?
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04-27-2011, 12:05 PM #10
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04-27-2011, 12:40 PM #11
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04-27-2011, 12:42 PM #12
No need for fancy calculators, until I got to university.. And there's no such thing as division by zero! It simply does not exist; nor is possible..
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04-27-2011, 12:47 PM #13
No problem man.. Just let me know if you need more help or clarification on this.. I noticed that I omitted a negative sign on the step below. I wish I could've shown you the hand written solution.
--Simplyfing it a bit further, you get:
d/dx = -(x-2)/(x+1) = 1/-((x+1)(x-2)/(x+1)^2))
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04-27-2011, 12:51 PM #14
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I had to take up to calc2 in college. That's when i lost most of my hair.
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04-27-2011, 03:17 PM #16
lo d hi - hi d low denominator squared we go!
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